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The molality of 1M NaNO(3) solution is (...

The molality of 1M `NaNO_(3)` solution is (d=1.25 g/ml)

A

0.8 m

B

0.858 m

C

1.6 m

D

1 M `Na_(2)SO_(4)`

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The molarity of NaNO_(3) solution is 1 M. The density of solution is 1.25 g/ml. Calculate molality of solution. (Molar-Mass of NaNO_(3)=85 g ).

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Knowledge Check

  • Molality of 1 M NaNO_3 solution (Density of solution is 1.25 g Ml^(-1) and mol. wt. of NaNO_3 = 85 g mol^(-1) ) is

    A
    1.286 m
    B
    4.44 m
    C
    0.858 m
    D
    none of these.

  • Density of 2M NaCI solution is 1.25 g/cc.The molality of the solution is :

    A
    2.79 molal
    B
    0.279 molal
    C
    1.279 molal
    D
    3,85 molal

  • The density of 3M solution of NaCl is 1.25 g mL^(-1) . The molality of the solution is

    A
    `3.86 mol kg^(-1)`
    B
    `1.97 mol kg^(-1)`
    C
    `2.79 mol kg^(-1)`
    D
    `0.786 mol kg^(-1)`

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