The equivalent weight of `K_(2)Cr_(2)O_(7)` in acidic medium is expressed in terms of its molecular weight (M) as-

Options

A. `(M)/(3)`
B. `(M)/(4)`
C. `(M)/(6)`
D. `(M)/(12)`

Answer

C

Explanation

In acidic medium, `K_(2)Cr_(2)O_(7)` undergoes reduction, forming `Cr^(3+)` ion .
`CrO_(7)^(2-)+14^(+)+6eto2Cr^(3+)+7H_(2)O`
In this reaction , the equivalent weight of `K_(2)Cr_(2)O_(7)`
`("Molecular weight "of K_(2)Cr_(2)O_(7))/("No of electrons gained by a molecule "of K_(2)Cr_(2)O_(7)"in its reduction")=(M)/(6)`