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The equivalent weight of K(2)Cr(2)O(7) i...

The equivalent weight of `K_(2)Cr_(2)O_(7)` in acidic medium is expressed in terms of its molecular weight (M) as-

A

`(M)/(3)`

B

`(M)/(4)`

C

`(M)/(6)`

D

`(M)/(12)`

Text Solution

Verified by Experts

The correct Answer is:
C
In acidic medium, `K_(2)Cr_(2)O_(7)` undergoes reduction, forming `Cr^(3+)` ion .
`CrO_(7)^(2-)+14^(+)+6eto2Cr^(3+)+7H_(2)O`
In this reaction , the equivalent weight of `K_(2)Cr_(2)O_(7)`
`("Molecular weight "of K_(2)Cr_(2)O_(7))/("No of electrons gained by a molecule "of K_(2)Cr_(2)O_(7)"in its reduction")=(M)/(6)`
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Knowledge Check

  • The equivalent weight of K_2Cr_2O_7 in acidic medium is expressed in terms of its molecular weight (M) as

    A
    `M/3`
    B
    `M/4`
    C
    `M/6`
    D
    `M/7`

  • K_(2)Cr_(2)O_(7) in acidic medium coverts into-

    A
    `Cr^(2+)`
    B
    `Cr^(3+)`
    C
    `Cr^(4+)`
    D
    `Cr^(5+)`

  • 0.6 moles of K_(2)Cr_(2)O_(7) can oxidise-

    A
    3.6 mol of `FeSO_(4)` to `Fe_(2)(SO_(4))_(3)`
    B
    0.1 mol of `FeSO_(4)` to `Fe_(2)(SO_(4))_(3)`
    C
    0.05 mol of `Sn^(+2)` to `Sn^(+4)`
    D
    1.8 mol of `Sn^(+2)` to `Sn^(+4)`

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