The bond dissociation energy ( E) and bond length ( R) of `O_(2),N_(2)` and `F_(2)` follow the order as :

Options

A. ARH_19Y_SP_24_04_18_01_E03_005
B. ARH_19Y_SP_24_04_18_01_E03_005
C. ARH_19Y_SP_24_04_18_01_E03_005
D. ARH_19Y_SP_24_04_18_01_E03_005

Answer

C

Explanation

Greater the bond order shorter is the bond length and thus stronger is the bond. Since for the given molecules bond order follows the trend
`underset((B.O=3))(N_(2))gtunderset((B.O=2))(O_(2))gtunderset((B.O=2))(F_(2))`
Thus the bond length decreases as `F_(2) gt O_(2)gt N_(2)` and bond dissociation energy follows the trend `N_(2) gt O_(2) gt F_(2)` .