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The bond dissociation energy ( E) and bo...

The bond dissociation energy ( E) and bond length ( R) of `O_(2),N_(2)` and `F_(2)` follow the order as :

A

ARH_19Y_SP_24_04_18_01_E03_005

B

ARH_19Y_SP_24_04_18_01_E03_005

C

ARH_19Y_SP_24_04_18_01_E03_005

D

ARH_19Y_SP_24_04_18_01_E03_005

Text Solution

Verified by Experts

The correct Answer is:
C

Greater the bond order shorter is the bond length and thus stronger is the bond. Since for the given molecules bond order follows the trend
`underset((B.O=3))(N_(2))gtunderset((B.O=2))(O_(2))gtunderset((B.O=2))(F_(2))`
Thus the bond length decreases as `F_(2) gt O_(2)gt N_(2)` and bond dissociation energy follows the trend `N_(2) gt O_(2) gt F_(2)` .
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  • The C-C bond dissociation energy is

    A
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    B
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  • Bond energy of Cl_(2),Br_(2) and I_(2) follow the order

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    `Cl_(2) gt Br_(2) gt I_(2)`
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    `Br_(2) gt Cl_(2) gt I_(2)`
    C
    `I_(2) gt Br_(2) gt Cl_(2)`
    D
    `I_(2) gt Cl_(2) gt Br_(2)`
  • Bond energy of Cl_(2),Br_(2) and I_(2) follow the order

    A
    `Cl_(2) gt Br_(2) gt I_(2)`
    B
    `Br_(2) gt Cl_(2) gt I_(2)`
    C
    `I_(2) gt Br_(2) gt Cl_(2)`
    D
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