If `CO_(2)` gas having a partial pressure of 1.67 bar is bubbled through 1 L water at 298 K the amount of `CO_(2)` dissolved in water in g `L^(-1)` is approximately. (Henry's law constant of `CO_(2)` is 1.67 K bar at 298 K )`

Options

A. 24.42
B. 12.21
C. 2.44
D. 1.22

Answer

C

Explanation

Let `P_(A) ` be the partial pressure of `CO_(2)` and `chi_(A)` be its mole fraction
`P_(A) = K_(H)chi_(A)` (Henry .s law )
1.67 bar = 1.67 K bar `xx chi_(A)`
(where , `x_(A)= 0.001)`
or `(n_(A))/(n_(B))`= 0.001
[ `because ` Number of moles of water = 55]
`n_(A) = 0.001xx 55.55 `
`n_(A)= 0.056`
`n = ("Given mass"(m))/("Molecular mass"(M))= 0.056`
`:. m = 0.056xx44 = 2.44` g
Thus 2.44 g of `CO_(2)` is dissolved in 1 L water at 298 K.