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A physicaI quantity P is reIated to four...

A physicaI quantity P is reIated to four observabIes a, b, c and d as foIIows:
P = `a^(3)b^(2)//(sqrt(cd))`
The percentage errors of measurement in a,b, c and d are 1%, 3%, 4% and 2%, respectiveIy. What is the percentage error in the quantity P? If the vaIue of p caIcuIated using the above reIation turns out to be 3.763 to what vaIue shouId you round off the resuIt?

Text Solution

Verified by Experts

The correct Answer is:
13%; 3.8
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