Home
Class 11
PHYSICS
Photon is the quantum of radiation with ...

Photon is the quantum of radiation with energy E = h`nu` where `nu` is frequency and h is Planck's constant. The dimension of h is the same as that of

A

linear impulse

B

angular impulse

C

linear momentum

D

angular momentum

Text Solution

Verified by Experts

The correct Answer is:
B, D
Promotional Banner

Topper's Solved these Questions

  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise Comprehension type|8 Videos
  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise Integer answer type|3 Videos
  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER ( Assertion-reason type )|7 Videos
  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise CBSE Scanner|9 Videos
  • NATURE OF VIBRATION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|2 Videos

Similar Questions

Explore conceptually related problems

As per quantum theory the energy E of a photon is related to its frequency nu as E = h nu , where h nu = Planck's constant. Then the dimension of h would be

The photon energy of a radiation is 1keV. What will be its (i) frequency, and (ii) wavelength?

The maximum energies of photoelectrons emitted by a metal are E_(1) and E_(2) when the incident radiation has frequencies f_(1) and f_(2) respectively. Show that Planck's constant h and the work function W_(0) of the metal are h = (E_(1) - E_(2))/(f_(1) - f_(2)), W_(0) = (E_(1) f_(2) - E_(2) f_(1))/(f_(1) - f_(2))

Which of the following quantities has the same dimension as that of Planck's constant?

The photon energy of a radiation is 2.55eV. Determine the frequency and wavelength of that radiation.

Consider the family of curves represented by the equation (x - h)^(2) + (y - k)^(2) = r^(2) where h and k are arbitrary constants . The differential equation of the above family is of order-

Consider the family of curves represented by the equation (x - h)^(2) + (y - k)^(2) = r^(2) where h and k are arbitrary constants . The differential equation of the above family is of curves -

The photon energy corresponding to a radiation of wavelength 5000 Å is 2.48eV. Find out Planck's constant from this data.

The ionization energy of hydrogen atom in the ground state is 1312 kJ "mol"^(-1) . Calculate the wavelength of radiation emitted when the electron in hydrogen atom makes a transition from n = 2 state to n = 1 state (Planck’s constant, h = 6.626 xx 10^(-34) Js , velocity of light, c = 3 xx 10^8 m s^(-1) , Avogadro’s constant, N_A = 6.0237 xx 10^23 "mol"^(-1) ).