Home
Class 11
PHYSICS
A lift with a mass 1200 kg is raised fro...

A lift with a mass 1200 kg is raised from rest by a cable with a tension 1350kgf. After some time the tension drops to 1000kgf and the lift comes to rest a height of 25 m above its initial point . ( 1 kgf=9.8 N).
What is the height at which the tension changes ?

A

10.8 m

B

12.5 m

C

14.3 m

D

16 m

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • FRICTION

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER ( Integer answer type )|1 Videos
  • FRICTION

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE with solutions (WBCHSE )|10 Videos
  • FRICTION

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER ( Multiple correct answers type )|3 Videos
  • FIRST AND SECOND LAW OF THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|18 Videos
  • HYDROSTATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|1 Videos

Similar Questions

Explore conceptually related problems

A lift of mass 200 kg is moving up with an acceleration of 4 m cdot s^(-2) . What is the tension in the lift cable? If the lift moves down with the same acceleration, what will be the tension in that case? [ g = 9.8 m cdot s^(-2) ]

A mass of 1 kg is suspended from the roof of a lift by a wire. The wire can withstand a maximum tension of 14.7 N. Find the limit of the acceleration of the lift for which the wire does not snap. G = 9.8 m cdot s^(-2)

A lift in a mine moves down 24m in 8 mins. If its moves in an uniform rate, let's find at what distance below the surface, it will be after 6 mins. If the lift starts from a height 10 m above the ground, let's find how deep the lift will go from the surface after 70 mins.

A path ball of mass 1g carrying an electric charge of 980 esu is dropped on a charged sphere of radius 10 cm from a height of 1m above the centre of the latter. It is found that the pith ball momentarily comes to rest on the charged sphere before being repelled away again. Calculate the charge on the sphere.

From what height should a stone be dropped so that the ratio of the distances traveled during the first and the last second of the fall is 1:9 ? Find the total time of its fall. [ g = 9.8 "m.s"^(-2) ].

A body of mass 1 kg is thrown with a velocity of 250 cm *s^(-1) , from a height 8m above the earth's surface . What will be its kinetic energy just before it touches the ground ?

A ball weighing 100 g was thrown veritcally upwards with a velocity 49 ms^(-1). At the same moment another indentical ball was dropped from a height of 98 m vertically above the first ball. After some time the two balls collided and got stuck together. This combined mass reached the ground finally. Determine how long the balls were in motion.