Home
Class 11
PHYSICS
A body of mass 2 kg starts from rest and...

A body of mass 2 kg starts from rest and moves with uniform acceleration . It acquires a velocity `20 m*s^(-1)` in 4 s.
(i) Power exerted on the body at 2s is

A

50W

B

100W

C

150W

D

200W

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WORK AND ENERGY

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Integer answer type )|1 Videos
  • WORK AND ENERGY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (WBCHSE)|27 Videos
  • WORK AND ENERGY

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Multiple correct answers type)|2 Videos
  • WBCHSE QUESTION PAPER -2019

    CHHAYA PUBLICATION|Exercise SECTION - II ( GROUP -D)|10 Videos

Similar Questions

Explore conceptually related problems

A body of mass m , starting from rest , moves with constant acceleration . After a time T it attains a velocity V. Show that the work done by the body in time t=1/2 m (V^2)/(T^2)*t^2*

A body starts from rest and moves with an acceleration proportionaI to time. (i) Find its velocity n s after starting. (ii) What distance will it traveI in n s?

Knowledge Check

  • A body of mass 2 kg starts from rest and moves with uniform acceleration . It acquires a velocity 20 m*s^(-1) in 4 s. (ii) Averrage power transferred to the body in first 2 s is

    A
    50W
    B
    100W
    C
    150W
    D
    200W
  • If a a body starts from rest and moves with uniform acceleration then

    A
    `v prop t`
    B
    `s prop t`
    C
    `v prop s`
    D
    `s prop sqrt t`
  • A body of mass m starts from rest with an acceleration t and gains a velocity V at time T . IF is the power which is given to that body then p=

    A
    `((mv^2)/(2T^2)) cdot t`
    B
    `((mv^2)/(2T^2)) cdot t^2`
    C
    `((mv^2)/(T^2)) cdot t`
    D
    `((mv^2)/(T^2)) cdot t^2`
  • Similar Questions

    Explore conceptually related problems

    Starting from rest, a wheel, with uniform acceleration, attains an angular velocity of 60 rad cdot s^(-1) at the end of 30 complete revolutions. What is the angular acceleration of the wheel?

    A particle starts from rest with a uniform acceleration and travels 57 cm in the 10th second. Find out this distance travelled in 12 s and the velocity at that instant.

    A particle, starting from rest, is in uniform acceleration. Its displacement in (P- 1) seconds and P seconds are s_(1) and s_(2) respectively . Then what would be its displacement in the (P^(2)-P+1) -th second?

    The acceleration of a particle starting from rest moving in a straight line with uniform acceleration is 8m//sec^2 . The time taken by the particle to move the second metre is:

    A car starts from rest and travels a distance s with a uniform acceleration f, then it travels with uniform velocity for a time t, and at last comes to rest with a uniform retardation (f)/(2) . If the total distance travelled is 5s. Then