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The velocity of a 10 kg mass is increase...

The velocity of a 10 kg mass is increased from `2m *s^(-1)` to `4m*s^(-1)`. The amount of work done in doing so is

A

60J

B

20 J

C

120J

D

cannot be determined from the given data

Text Solution

Verified by Experts

The correct Answer is:
A
Amount of work
`=1/2 m(v_f^2-v_i^2) =1/2 xx5xx(4^2-2^2)=60 J`
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