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A particle of mass m is revolving along a circular path of radius r with uniform angular velocity `omega`. What will be the magnitude and direction of the angular momentum of that particle ?

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Knowledge Check

  • A particle is moving along a circular path of radius 5m and with uniform speed 5m/s. What will be the average acceleration when the particle completes half revolution ?

    A
    zero
    B
    `10 m/s^2`
    C
    `10 pi m/s^2`
    D
    `10/pi m/s^2`

  • A particle moves along a circular path of radius r with uniform speed v. The angle described by the particle in one second is given by

    A
    `v/r`
    B
    `v(-1)`
    C
    `vr^(-2)`
    D
    `v^2r`

  • The angular acceleration of a particle moving along a circular path with uniform speed is

    A
    Uniform but non zero
    B
    Zero
    C
    Variable
    D
    Cannot be predicted from the given information

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    A particle of mass m moves in a circular path of radius r in a horizontal plane with uniform angular velocity vec(omega) about the z- aixs. Write down the position vector of the particle at any instant and hence derive expressions for velocity and acceleration of the particle.

    A charge q is revolving along a circular path of radius r with velocity v . Determine its magnetic moment .

    Angular momentum of a body of mass m rotating along a circular path of radius r with uniform speed is L. What is the magnitude of the centripetal force acting on it?

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    An electron of charge e and mass m is moving in a circular path of radius r with a uniform angular speed omega . Then which of the following statements are correct ? The equivalent current flowing in the circular path is proportional to r^2 The magnetic moment due to circular current loop is independent of m The magnetic moment due to circular current loop is equal to 2e/m times the angular momentum of the electron The angular momentum of the particle is proportional to the areal velocity of electron

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