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A material particle of mass m is revolvi...

A material particle of mass m is revolving along a horizontal circular path of radius r under the influenece of the centripetal force = `-(k)/(r^(2)) `(k = constant ). What will be the total kinetic energy of the particle ?

Text Solution

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The correct Answer is:
`(k)/(2r)`
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Knowledge Check

  • If a particle of mass is moving in a horizontal circle of radius r with a centripetal force (k/r^2) the total energy is

    A
    (-k/2r)
    B
    (-k/r)
    C
    (-2k/r)
    D
    (-4k/r)

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