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Find the locus of the third vertex of a ...

Find the locus of the third vertex of a right angled triangle , the ends of whose hypotenuse are (4,0) and (0,4)

Text Solution

Verified by Experts

The correct Answer is:
`x^(2)+y^(2)-4x-4y=0`
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Knowledge Check

  • The maximum area of a right angled triangle with hypotenuse h is

    A
    `h^(2)//2 sqrt(2)`
    B
    `h^(2)//2`
    C
    `h^(2)//sqrt(2)`
    D
    `h^(2)//4`

  • If a right angled triangle is revolved about its hypotenuse then it will form a ………..

    A
    double cone
    B
    triple cone
    C
    only cone
    D
    none

  • The legs of a right triangle are a and b the linc segment of length d connecting the vertex of the right angle to a point P of the hypotenuse enclose an angle delta with the leg a. The quantities a, b, d and delta are correctly related as

    A
    `1/(2d) = (cos delta)/a + (sin delta)/b`
    B
    `2/d= (cos delta)/a + (sin delta)/b`
    C
    `1/d = (cos delta)/a + (sin delta)/b`
    D
    `2/d = (cos delta)/b + (sin delta)/a`

    • Similar Questions

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    Equilateral triangle are drawn on the three sides of a right angled Triangle. Show that the area of the Triangle on the hypotenuse is equal to the sum of the areas of triangle on the other two sides.

    The ends of the hypotenuse of a right angle triangle are (0,6) and (6,0) . Find the equation of locus of its third vertex.

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