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Ten coins are placed on top of each othe...

Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10g and acceleration due to gravity is `10 ms^(-2)`, what is the magnitude and direction of the force on the `7^(th)` coin (counting from the bottom) due to all the coins above it ?

A

0.3 N downwards

B

0.3 N upwards

C

0.7 N downwards

D

0.7 N upwards

Text Solution

Verified by Experts

The correct Answer is:
A
Force on the seventh coin = weight of the three coins above it. `F=3mg`
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