Home
Class 11
PHYSICS
An ice block is projected vertically up ...

An ice block is projected vertically up with a velocity 20 `ms^(-1)`. The amount of ice that melt when it reaches the ground and if the loss of P.E. is converted into heat energy if the mass of ice block is 4.2 kg

A

2.5gm

B

2.5kg

C

0.25kg

D

0.25gm

Text Solution

Verified by Experts

The correct Answer is:
A
Maximum height attained, `h=(u^(2))/(2g)`
`W=JHrArrmgh=J(xL_("ice"))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-II(C.W)|25 Videos

  • GRAVITATION

    NARAYNA|Exercise EXERCISE -IV|40 Videos

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - IV|35 Videos

Similar Questions

Explore conceptually related problems

Find the amount of heat released if 1kg steam at 200^(@)C is convered into -20^(@)C ice.

A man of mass 60kg sitting on ice pushes a block of mass of 12kg on ice horizontally with a speed of 5ms^(-1) .The coefficient of friction between the man and ice and between block and ice is 0.2. If g =10 ms^(-2) , the distance between man and the block, when they come to rest is

Knowledge Check

  • An ice cube of mass M_(0) is given a velocity v_(0) on a round horizontal surface with coefficient of friction mu . The block is at its melting point and latent heat of fusion of ice is L . The block receive heat only due to the friction forces and all work is converted into heat. Find the mass of the remaining ice block after time t.

    A
    `m=m_(0)e^(-(2mug)/(L)(V_(0)t+(1)/(2)mu"gt"^(2)))`
    B
    `m=m_(0)e^(-(2mu)/(L)(V_(0)t-(1)/(2)mu"gt"^(2)))`
    C
    `m=m_(0)e^(-(3mu)/(L)(V_(0)t-(1)/(2)mu"gt"^(2)))`
    D
    `m=m_(0)e^(-(2mu)/(L)(V_(0)t-mu"gt"^(2)))`

  • A 42 kg block of ice moving on rough horizontal surface stops due to friction, after sometime. If the initial velocity of the decelerating block is 4ms^-1 , the mass of ice (in kg) that has melted due to the heat generated by the friction is (Latent heat of ice is 3.36xx10^5Jkg^ -1

    A
    `1xx10^-3`
    B
    `1.5xx10^-3`
    C
    `2xx10^-3`
    D
    `2.5xx10^-3`

  • A man of mass 60kg sitting on ice pushes a block of mass 12kg on ice horizontally with a speed of 5ms^(-1) The coefficient of friction between the man and ice and between block and ice is 0.2 If g =10ms^(2) the distance beteen man and the block when they come to rest is .

    A
    `6m`
    B
    `6.5m`
    C
    `3m`
    D
    `7m`

    • Similar Questions

    Explore conceptually related problems

    A piece of ice falls from a heighth so that it melts completely. Only one-quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of height from which ice fall . [Latent heat of ice is 3.4 xx 10^(5) J//kg and g = 10 N/kg]

    A person of mass 72kg sitting on ice pushes a block of mass of 30kg on ice horizontally with a speed of 12ms^(-1) .The coefficient of friction between the man and ice and between block and ice is 0.02 .If g=10ms^(-1) ,the distance between man and the block, when they come to rest is

    A piece of ice falls from a heighth so that it melts.com Only one-quarter of the heat produced is absorteil ice and all energy of ice gets converted into beat de fall. The value of his [Latent heat of ice is 3.41 and g = 10 N/kg]:

    A piece of ice falls from a hight h so that it melts completely. Only one quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of h is : (Latent heat of ice is 3.4xx10^(5) j//kg and g=10N//kg )

    When 1 kg of ice at 0^(@)C melts to water at 0^(@)C , the resulting change in its entropy, taking latent heat of ice to be 80 cal//g is

    Home
    Profile