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If 3*01xx10^(20) molecules are removed f...

If `3*01xx10^(20)` molecules are removed from 98 mg of `H_(2)SO_(4)`, then the number of moles of `H_(2)SO_(4)` left are

A

`0.1xx10^(-3)`

B

`0.5xx10^(-3)`

C

`1.66xx10^(-3)`

D

`9.95xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
no of moles in 98 mg of
`H_(3)SO_(4)=(98xx10^(-3))/(98)=10^(-3)`
no of moles in `3xx10^(20)` molecules
`=(3xx10^(20))/(6xx10^(23))=0.5xx10^(-3)`
`therefore" mo of moles left "=1xx10^(-3)-0.5xx10^(-3)=0.5xx10^(-3)`
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