0.302 g of organic compound gave 0.268 g of silver bromide . The percentage of bromine in the sample is

Options

A. 20
B. 50
C. 37.75
D. 75

Answer

To find the percentage of bromine in the organic compound using the data provided, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Weight of organic compound (W_organic) = 0.302 g
- Weight of silver bromide (W_AgBr) = 0.268 g
- Atomic weight of bromine (Br) = 80 g/mol
- Atomic weight of silver (Ag) = 108 g/mol

2. **Use the Formula for Percentage of Bromine:**
The formula to calculate the percentage of halogen (in this case, bromine) using the Carrie's method is:
\[ \text{Percentage of Bromine} = \left( \frac{\text{Atomic weight of Br}}{\text{Atomic weight of Br} + \text{Atomic weight of Ag}} \right) \times \left( \frac{\text{Weight of AgBr}}{\text{Weight of organic compound}} \right) \times 100 \]

3. **Substitute the Values into the Formula:**
- Atomic weight of Br = 80 g/mol
- Atomic weight of Ag = 108 g/mol
- Substitute the values into the formula:
\[ \text{Percentage of Bromine} = \left( \frac{80}{80 + 108} \right) \times \left( \frac{0.268}{0.302} \right) \times 100 \]

4. **Calculate the Denominator:**
\[ 80 + 108 = 188 \]

5. **Calculate the Fraction:**
\[ \frac{80}{188} \approx 0.4255 \]
\[ \frac{0.268}{0.302} \approx 0.8861 \]

6. **Combine the Results:**
Now, multiply the two fractions:
\[ 0.4255 \times 0.8861 \approx 0.3775 \]

7. **Convert to Percentage:**
\[ 0.3775 \times 100 \approx 37.75\% \]

### Final Answer:
The percentage of bromine in the organic compound is **37.75%**.

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