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10mL of gaseous hydrocarbon on combustio...

`10mL` of gaseous hydrocarbon on combustion gives `40ml` of `CO_(2)(g)` and `50mL` of `H_(2)O` (vapour) The hydrocarbon is .

A

`C_(4)H_(8)`

B

`C_(4)H_(10)`

C

`C_(5)H_(10)`

D

`C_(5)H_(12)`

Text Solution

Verified by Experts

The correct Answer is:
B
`N=("wt in grams")/("gm Eq. wt")xx(100)/("V in ml.")`
`=(1.26)/(63)xx(1000)/(250)`
`=0.08N`
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