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The following equilibrium constants are ...

The following equilibrium constants are given :
` N_(2) + 3 H_(3) hArr 2 NH_(3) , K_(1)`
` N_(2) + O_(2) hArr 2 NO , K_(2)`
` H_(2) + 1/2 O_(2) hArr H_(2) O , K_(3)`
The equilibrium constant for the oxidation of `NH_(3)` by oxygen to give NO is :

A

`K_(1)K_(2)//K_(3)`

B

`K_(2)K_(3)^(3)//K_(1)`

C

`K_(2)K_(3)^(2)//K_(1)`

D

`K_(2)^(2)K_(3)//K_(1)`

Text Solution

Verified by Experts

For equilibrium `K_(1)=([NH_(3)]^(2))/([N_(2)] [H_(2)]^(3)) ........(i)`
`K_(2)=([NO]^(2))/([N_(2)] [O_(2)]) ..........(ii)`
`K_(3)=([H_(2)O])/([H_(2)] [O_(2)]^(1//2))......(iii)`
For a reaction, [oxidation of `NH_(3)` by oxygen to given NO]
`2NH_(3) (g) +5/2 O_(2) (g) Leftrightarrow 2NO(g)+ 3H_(2)O (g)`
`K=([NO]^(2) [H_(2)O]^(3))/([NH_(3)]^(2) [O_(2)]^(5//2)) ..........(iv)`
For getting K, we must do
`K_(3)^(3)=([H_(2)O]^(3) [O_(2)]^(3//2)) .........(v)`
from equation (i), (ii) and (v) `K=(K_(2) xx K_(3)^(3))/(K_(1))`
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Knowledge Check

  • The following equilibrium constants are given: N_(2) + 3H_(2) 2NH_(3) , K_(1) N_(2) + O_(2) 2NO , K_(2) H_(2) + 1//2 O_(2) H_(2)O , K_(3) The equilibrium constant for the oxidaton of 2 mole NH_(3) by oxygen to give NO is

    A
    `(K_(2)K_(3)^(3))/(K_1)`
    B
    `(K_(2)^(2)K_(3)^(2))/(K_1)`
    C
    `(K_(1)K_(2))/(K_3)`
    D
    `(K_(2)K_(3)^(2))/(K_1)`

  • The following equilibrium constants are given : N_(2)+3H_(2)iff2NH_(3),K_(1) N_(2)+O_(2)iff2NO,K_(2) H_(2)+(1)/(2)O_(2)iffH_(2)O,K_(3) The equilibrium constant for the oxidation of 2 mol of NH_(3) to give NO is

    A
    `K_(1).(K_(2))/(K_(3))`
    B
    `K_(2).(K_(3)^(3))/(K_(1))`
    C
    `K_(2).(K_(3)^(2))/(K_(1))`
    D
    `K_(2)^(2).(K_(3))/(K_(1))`

  • The equilibrium conastants of the following are N_(2) + 3H_(2) hArr 2 NH_(3) " " K_(1) N_(2) + O_(2) hArr 2 NO " " K_(2) H_(2) + 1/2 O_(2) hArr H_(2)O " " K_(3) The equilibrium constant (K) of the reaction 2 NH_(3) + 5/2 O_(2) overset (K) hArr 2 NO + 3 H_(2) O 2 NH_(3) + 5/2 O_(2) overset (K) hArr 2 NO + 3 H_(2) O will be

    A
    ` K_(1) K_(3)^(3) //k_(2)`
    B
    ` K_(2) K_(3)^(3) //K_(1)`
    C
    `K_(2) K_(3) //K_(1) `
    D
    `K_(2)^(3) K_(3) // K_(1)`
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