`{:("Column -I","Column -II"),(("Atomic no. of elemets"),"(IUPAC name)"),((A)105,(P)"Unn"),((B)107,(Q)"Uns"),((C )109,(R )"Unp"),((D)110,(S)"Une"):}`

Options

A. A-R, B-P, C-S, D-Q
B. A-P, B-R, C-S, D-Q
C. A-R, B-Q, C-S, D-P
D. A-Q, B-R, C-S, D-P

Answer

To solve the problem of matching the atomic numbers of elements with their corresponding IUPAC names, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Numbers and Their Corresponding IUPAC Names:**
We have the following atomic numbers and need to find their IUPAC names:
- (A) 105
- (B) 107
- (C) 109
- (D) 110

2. **Determine the IUPAC Naming Convention:**
The IUPAC naming convention for elements beyond atomic number 100 generally follows a pattern:
- The first digit (1) is represented as "un".
- The second digit (0) is represented as "nil".
- The third digit is represented as:
- 0 = nil
- 1 = un
- 2 = bi
- 3 = tri
- 4 = quad
- 5 = pent
- 6 = hex
- 7 = sept
- 8 = oct
- 9 = non

3. **Match Each Atomic Number with Its IUPAC Name:**
- **For 105:**
- 1 = un
- 0 = nil
- 5 = pent
- IUPAC Name: **Unnilpentium (Unp)** → Match with (C) (R)

- **For 107:**
- 1 = un
- 0 = nil
- 7 = sept
- IUPAC Name: **Unnilseptium (Uns)** → Match with (B) (Q)

- **For 109:**
- 1 = un
- 0 = nil
- 9 = non
- IUPAC Name: **Unnilennium (Une)** → Match with (C) (S)

- **For 110:**
- 1 = un
- 1 = un
- 0 = nil
- IUPAC Name: **Ununnium (Uun)** → Match with (D) (P)

4. **Final Matching:**
- (A) 105 → (R) Unnilpentium
- (B) 107 → (Q) Unnilseptium
- (C) 109 → (S) Unnilennium
- (D) 110 → (P) Ununnium

### Summary of Matches:
- A (105) → R (Unnilpentium)
- B (107) → Q (Unnilseptium)
- C (109) → S (Unnilennium)
- D (110) → P (Ununnium)

### Final Answer:
The correct matches are:
- A → R
- B → Q
- C → S
- D → P