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(CH(3))(2)CHBr overset((1)Li)underset((2...

`(CH_(3))_(2)CHBr overset((1)Li)underset((2)CuI, (3)(CH_(3))_(2)CHCH_(2)Br)rarrA`. This is Corey - House method of synthesis of A which is :

A

`(CH_(3))_(2)CHCH_(2)CH(CH_(3))_(2)`

B

`(CH_(3))_(2)CHCH_(2)CH_(2)CH_(3)`

C

`(CH_(3))_(2)CHCH_(2)CH_(2)CH_(2)CH_(3)`

D

None of correct

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem using the Corey-House method, we will follow these steps: ### Step 1: Identify the starting material The starting compound is (CH₃)₂CHBr, which is 2-bromopropane. ### Step 2: Reaction with Lithium When (CH₃)₂CHBr reacts with lithium (Li), it forms a lithium alkyl intermediate. The bromine atom (Br) is replaced by lithium, resulting in the formation of (CH₃)₂CHLi (lithium 2-propyl). ### Step 3: Reaction with Copper(I) Iodide Next, the lithium alkyl intermediate (CH₃)₂CHLi is treated with copper(I) iodide (CuI). This forms a reagent known as R₂CuLi, where R is the alkyl group. In this case, it will yield (CH₃)₂CHCuLi. ### Step 4: Reaction with the second alkyl halide Now, (CH₃)₂CHCuLi acts as a nucleophile and will react with another alkyl halide, which is (CH₃)₂CHCH₂Br. The nucleophile attacks the carbon atom bonded to the bromine in the second alkyl halide, leading to the formation of a new carbon-carbon bond. ### Step 5: Formation of product A The result of this reaction is the formation of the product A, which is (CH₃)₂CHCH₂(CH₃) (or 3-methylbutane). The bromine atom leaves, and we have a new alkane formed. ### Final Answer Thus, the final product A is 3-methylbutane. ---
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Knowledge Check

  • Consider the following reaction (CH_3)_2CHBrunderset((iii)(CH_3)_2CHCH_2Br)overset((i)Li, (ii)Cul)(to)A This is corey - house method of synthesis of A which is

    A
    `(CH_3)_2CHCH_2CH(CH_3)_2`
    B
    `(CH_3)_2CHCH_2CH_2CH_3`
    C
    `(CH_3)_2CHCH_2CH_2CH_2CH_3`
    D
    None of the above
  • CH_(3)underset(CH_(3))underset(|)CHCH=CH_(2)overset(HBr)rarrA A (predominantly) is

    A
    `CH_(3)underset(CH_(3))underset(|)CHCH(Br)CH_(3)`
    B
    `CH_(3)underset(CH_(3))underset(|)overset(Br)overset(|)C CH_(2)CH_(3)`
    C
    `BrCH_(2)CH_(2)underset(CH_(3))underset(|)CHCH_(3)`
    D
    `BrCH_(2)underset(CH_(3))underset(|)CHCH_(2)CH_(3)`
  • CH_(3)CH_(2)CH_(3) overset(Cl_(2))underset(hv)(to) A overset(Br_(2))underset(hb)(to)B A and B are :

    A
    `CH_(3)CH_(2)CH_(2)Cl" and " CH_(3)overset(Br)overset(|)CH-CH_(2)-Cl`
    B
    `CH_(3)overset(Cl)overset(|)CHCH_(3) " and " CH_(3)overset(Br)overset(|)CHCH_(2)-Cl`
    C
    `CH_(3)overset(Cl)overset(|)CHCH_(3) " and "CH_(3)overset(Cl)overset(|)CH-CH_(2) -Br`
    D
    `CH_(3)overset(Cl)overset(|)CHCH_(3)" and " CH_(3)-overset(Cl)overset(|)underset(Br)underset(|)C-CH_(3)`
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