Three moles of glyoxal are obtained by the ozonolysis, followed by hydrolysis (in presence of Zn) os

Options

A. `C_(2)H_(2)`
B. `C_(2)H_(4)`
C. `C_(6)H_(6)`
D. `C_(6)H_(12)`

Explanation

To determine the reactant that yields three moles of glyoxal (CHO) through ozonolysis followed by hydrolysis in the presence of zinc, we can follow these steps:

### Step 1: Understand the Product
Glyoxal has the structure:
\[ \text{CHO} \text{CHO} \]
This means that we need to produce three moles of glyoxal, which can be represented as:
\[ 3 \times \text{CHO} \]

### Step 2: Identify the Reaction Process
The process involves ozonolysis followed by hydrolysis. Ozonolysis typically occurs with alkenes or alkynes, resulting in the cleavage of double or triple bonds to form carbonyl compounds.

### Step 3: Determine the Required Reactant
To produce three moles of glyoxal, we need to find a suitable reactant. A compound that can yield three moles of glyoxal upon ozonolysis is 1,3-hexadiene. The structure of 1,3-hexadiene is:
\[ \text{H}_2C=CH-CH=CH-CH_2-CH_3 \]

### Step 4: Perform Ozonolysis
When 1,3-hexadiene undergoes ozonolysis, it cleaves at the double bonds:
1. The first double bond (between C1 and C2) will yield one molecule of glyoxal.
2. The second double bond (between C3 and C4) will yield another molecule of glyoxal.

### Step 5: Hydrolysis
After ozonolysis, the ozonide formed will be hydrolyzed in the presence of zinc, resulting in the formation of glyoxal. The hydrolysis will convert the ozonide into carbonyl compounds.

### Step 6: Count the Moles of Glyoxal
From the ozonolysis of 1,3-hexadiene, we can obtain:
- 1 mole from the first double bond
- 1 mole from the second double bond
- 1 additional mole from the hydrolysis process

Thus, we end up with a total of three moles of glyoxal.

### Conclusion
The reactant that yields three moles of glyoxal upon ozonolysis followed by hydrolysis in the presence of zinc is **1,3-hexadiene (C6H10)**.

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