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Time required to decompose half the s...

Time required to decompose half the substance for a `n^(th)` order reaction is inversely proportional to : (Given that a : initial concentration):

A

`a^(n+1)`

B

`a^(n-1)`

C

`a^(n-2)`

D

`a^(n)`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The time required to decompose half of the reactant for an nth-order reaction is inversely proportional to (a is the initial concentration)

    A
    `a^(n)`
    B
    `a^(n-2)`
    C
    `a^(n-1)`
    D
    `a^(n+1)`

  • If a is the initial concentration then time required to decompose half of the substance for nth order is inversely proportional to:

    A
    `a^(n)`
    B
    `a^(n-1)`
    C
    `a^(1-n)`
    D
    `a^(n-2)`

  • Half life time for second order reaction is proportional

    A
    initial concentration of the reactant
    B
    independent of initial concentration
    C
    inversely proportional to initial concentration
    D
    `prop ( 1)/(["concentration"]^(2) )`

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    Half-life of a reaction is found to be inversely proportional to the cube of initial concentration. The order of reaction is

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    A : The rate constant of zero order reaction is equal to rate of reaction. R : t_(1//2) for zero order reaction is directly proportional to initial concentration.

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