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The equilibrium constant of the reactio...

The equilibrium constant of the reaction is 10 . Calculate the value of `DeltaG^(Ө)`, Given `R=8.314 JK^(-1) "mol"^(-1)`, T=300 K

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`DeltaG^(Ө)`=-RT ln K =-2.303 RT log K
`R=8.314 JK^(-1) "mol"^(-1) `, T=300 K , K=10
`DeltaG^(Ө)=-2.303xx8.314JK^(-1) "mol"^(-1) xx (300 K) xx log 10`
`=-5527 "J mol"^(-1) =- 5.527 "kJ mol"^(-1)`
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