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(a^m)/(a^n)=a^(m//n)(a ne 0)...

`(a^m)/(a^n)=a^(m//n)(a ne 0)`

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Knowledge Check

  • The following are the step involved proving that a^(m)xxa^(n)=a^(m+n) , where a ne 0,a ne 1" and "a ne -1 . Arrange them in sequential order. (A) a^(m)xxa^(n)= (a xx a xx"......"m" times ")xx(axxaxx"...."n" times ") (B) a^(m)xxa^(n)=a^(m+n) (C ) a^(m) =axxaxx"….."m" times " , a^(n)=axxaxx"...."n" times " (D) a^(m) xxa^(n) =axxaxx"...."(m+n) times

    A
    CABD
    B
    ACDB
    C
    ACBD
    D
    CADB

  • If (a^(m))^(n)=a^(m^(n)) , then express 'm' in the terms of n is (agt0, ane0, mgt1, ngt1)

    A
    `n^((1/(n-1)))`
    B
    `n^((1/(n+1)))`
    C
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    D
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  • If a^m .a^n = a^(mn) , then m(n - 2) + n(m- 2) is :

    A
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    B
    1
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    D
    `1/2`

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