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if (x-y)^3=216 and (x-y)^5=32, then find...

if `(x-y)^3=216 and (x-y)^5=32`, then find `x^3-y^3`.
The following steps are involved in solving the above problem. Arrange them in sequential order.
(A) Therefore, `x-y=6 and x+y=2`.
(B) Solving `x-y=6 and x+y=2rArrx=4, y=-2`.
(C) `x^3-y^3=64-(-2)^3=64+8=72`
(D) `(x-y)^3=216rArr(x-y)^3=6^3rArr x-y=6 and (x+y)^5=32rArr (x+y)^5=2^5rArr x+y=2`.

A

DABC

B

DBAC

C

DCBA

D

BDCA

Text Solution

Verified by Experts

The correct Answer is:
A
(D), (A),(B), and (C) is the required sequential order.
Hence, the correct option is (a).
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Knowledge Check

  • If (x-y)^(3)=216 and (x+y)^(5)=32 , then find x^(3)-y^(3) . The following stpes are involved in solving the above problem. (A) Therefore x-y=6 and x+y=2 . (B) Solving x-y=6 and x+y=2 rArr x=4, y=-2 (C) x^(3)-y^(3)=64-(-2)^(3)=64+8=72 (D) (x-y)^(3)=216 rArr (x+y)^(5)=2^(5) rArr x+y=2

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  • If (2x^2-y^2)^4=256 and (x^2+y^2)^5=243 , then find x^4-y^4 The following steps are involved in solving the above problem. Arragne then in sequential order. (A) (x^2-y^2)^4=256=4^4 and (x^2+y^2)^5=3^5 (B) x^4-y^4=12 (C) (x^2-y^2)(x^2+y^2)=4xx3 (D) x^2-y^2=4 and x^2+y^2=3

    A
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  • If (x^(2)-y^(2))^(4)=256 and (x^(2)+y^(2))^(5)=243 then find x^(4)-y^(4) . The following steps are involved in solving the above problem. Arrange them in sequential order. (A) (x^(2)-y^(2))^(4)=256= 4^(2) and (x^(2)+y^(2))^(5)=3^(5) (B) (x^(2)-y^(2)) (x^(2)+y^(2))=4xx3 (C) x^(2)-y^(2)=4 and x^(2)+y^(2)=3 (D) x^(2)-y^(2)=4 and x^(2)+y^(2)=3

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