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If (2x^2-y^2)^4=256 and (x^2+y^2)^5=243,...

If `(2x^2-y^2)^4=256 and (x^2+y^2)^5=243`, then find `x^4-y^4`
The following steps are involved in solving the above problem. Arragne then in sequential order.
(A) `(x^2-y^2)^4=256=4^4 and (x^2+y^2)^5=3^5`
(B) `x^4-y^4=12`
(C) `(x^2-y^2)(x^2+y^2)=4xx3`
(D) `x^2-y^2=4 and x^2+y^2=3`

A

ADCD

B

ABCD

C

ADBC

D

ACDB

Text Solution

Verified by Experts

The correct Answer is:
A
(A),(D),(C) and (B) is the required sequentail order. Hence the correct option is (a).
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Knowledge Check

  • If (x^(2)-y^(2))^(4)=256 and (x^(2)+y^(2))^(5)=243 then find x^(4)-y^(4) . The following steps are involved in solving the above problem. Arrange them in sequential order. (A) (x^(2)-y^(2))^(4)=256= 4^(2) and (x^(2)+y^(2))^(5)=3^(5) (B) (x^(2)-y^(2)) (x^(2)+y^(2))=4xx3 (C) x^(2)-y^(2)=4 and x^(2)+y^(2)=3 (D) x^(2)-y^(2)=4 and x^(2)+y^(2)=3

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