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The atomic mass of helium is 232 and its...

The atomic mass of helium is 232 and its atomic number is 90. During the course of its radioactive disintegration `6 alpha` and `4 beta`-particles are emitted. What is the atomic and atomic number of the final atoms?

Text Solution

Verified by Experts

Decrease in mass due to emission of `6 alpha` particles `= 6 xx 4 = 24`
So, Atomic mass of the product atom = (232 - 24) = 208)
No of `beta` particles emitted = 2 `xx` No . of `alpha` particle
`- (Z_("Thorium") - Z_("Final atom"))`
`4 = 2 xx 6 - (90 - Z_("Final atom"))`
or `Z_("Final atom") = 82`
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  • The atomic number of Potassium is 19 and its mass number is 39. The number of neutrons its atom is

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