Nucleus of an atom resembles with a drop...

Nucleus of an atom resembles with a drop of liquid. Density of nucleus is very high, i.e., `10^(8)` tonne/cc or 130 trillion tonnes `m^(-3)`. This density is about a trillion times greater than that of water. Density of nuclei of all elements are same, it is independent of atomic number or atomic mass. However, the radius of nucleus depends on the mass number . Surface However, the radius of nucleus depends on the mass number. Surface tension of nucleus is also very high. i.e., about `1.24 xx 10^(18)` times, the suface tension of water.
The radius of `._(6)^(12)C` nucleus is:

`5 xx 10^(-15) m`

`1.4 xx 10^(-15) m`

`3.5 xx 10^(-15) m`

`6 xx 10^(-15) m`

Verified by Experts

The correct Answer is:

`r = r_(0) A^(1//2)` where A = mass number `r_(0) = 1.4 xx 10^(-15) m`

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Nucleus of an atom resembles with a drop of liquid. Density of nucleus is very high, i.e., 10^(8) tonne/cc or 130 trillion tonnes m^(-3) . This density is about a trillion times greater than that of water. Density of nuclei of all elements are same, it is independent of atomic number or atomic mass. However, the radius of nucleus depends on the mass number . Surface However, the radius of nucleus depends on the mass number. Surface tension of nucleus is also very high. i.e., about 1.24 xx 10^(18) times, the suface tension of water. Ratio of volume of atom and nucleus is:

`10^(8) : 1`

`10^(15) : 1`

`10^(13) : 1`

`10^(12) : 1`

`A^(2)`

`A^(1//3)`

`[A]^(3)`

`(A)^(2)`

`(A)^(0)`

`(A)^(1//3)`

`(A)`