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5.5 mg of nitrogen gas dissolves in 180 ...

5.5 mg of nitrogen gas dissolves in 180 g of water at 273 K and one atm pressure due to nitrogen gas. The mole fraction of nitrogen in 180 g of water at 5 atm nitrogen pressure is approximately

A

`1xx10^(-6)`

B

`1xx10^(-5)`

C

`1xx10^(-3)`

D

`1xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

Solubility of a gas `prop` mole fraction
`n_(N_(2))=(5.5xx10^(-3))/(28)=1.96xx10^(-4)` at 1 atm
Now, p `prop` mole fraction
then at 5 atm, the mole fraction will increase 5 times.
Hence, `5xx1.96xx10^(-4)= 9.8xx10^(-4)~~10xx10^(-4)= 1.0xx10^(-3)`
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Knowledge Check

  • 5.5 mg of nitrogen gas dissolves in 180g of water at 273 K and one atm pressure due to nitrogen gas. The mole fraction of nitrogen in 180 g of water at 5 atm nitrogen pressure is approximately

    A
    ` 1 xx 10^(-5)`
    B
    `1 xx 10^(-4)`
    C
    `1 xx 10^(-6)`
    D
    `1 xx 10^(-3)`
  • 5.85 g of NaCl are dissolved in 90 g of water, the mole fraction of NaCl is :

    A
    0.1
    B
    0.01
    C
    0.2
    D
    0.0196
  • If 22.4 ml of a triatomic gas has a mass of 0.048 g at 273K and 1 atm pressure, then the mass of one atom is:

    A
    `7.9 xx 10^(-23) g `
    B
    `2.6 xx 10^(-23) g `
    C
    `2.4 xx 10^(-22) g `
    D
    `2.4 xx 10^(-23) g `
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