5.5 mg of nitrogen gas dissolves in 180 g of water at 273 K and one atm pressure due to nitrogen gas. The mole fraction of nitrogen in 180 g of water at 5 atm nitrogen pressure is approximately

Options

A. `1xx10^(-6)`
B. `1xx10^(-5)`
C. `1xx10^(-3)`
D. `1xx10^(-4)`

Answer

C

Explanation

Solubility of a gas `prop` mole fraction
`n_(N_(2))=(5.5xx10^(-3))/(28)=1.96xx10^(-4)` at 1 atm
Now, p `prop` mole fraction
then at 5 atm, the mole fraction will increase 5 times.
Hence, `5xx1.96xx10^(-4)= 9.8xx10^(-4)~~10xx10^(-4)= 1.0xx10^(-3)`