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0.30g of an organic compound containing ...

`0.30g` of an organic compound containing `C`, `H` and Oxygen on combustion yields `0.44g CO_(2)` and `0.18g H_(2)O`. If one mole of compound weighs `60`, then molecular formula of the compound is

A

`C_(3)H_(8)O`

B

`C_(2)H_(4)O_(2)`

C

`CH_(2)O`

D

`C_(4)H_(6)O`

Text Solution

Verified by Experts

The correct Answer is:
B
Percentage of `C=(12)/(44)xx(0.44)/(0.30)xx100=40%`
Percentage of `=(2)/(18)xx(0.18)/(0.30)xx100=6.6%`
percentate of `O=100-(40+6.6)=53.4%`

Hence, empirical formula `=CH_(2)O`
`n=("Molecular mass")/("Empirical formula mass")=(60)/(30)=2`
`rArr` Molecular formula of compound `=(CH_(2)O)_(2)`
`=C_(2)H_(4)O_(2)`
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Knowledge Check

  • 0.30 g of an organic compound containing C, H and oxygen on combustion yields 0.44 g CO_2 and 0.18 g H_2O . If one mol of compound weighs 60, then molecular formula of the compound is

    A
    `C_3H_8O`
    B
    `C_2H_4O_2`
    C
    `CH_2O`
    D
    `C_4H_6O`.

  • 0.30 g of an organic compound containing C, H and oxygen on combustion yields 0.44 g CO_2 and 0.18 g H_2O . If one mol of compound weighs 60, then molecular formula of the compound is

    A
    `C_3H_8O`
    B
    `C_2H_4O_2`
    C
    `CH_2O`
    D
    `C_4H_6O`.

  • 0.30g of an organic compound contaiining C, H and Oxygen an combustion yields 0.44g CO_2 and 0.18g H_2O . If one mol of compound weight 60, then molecular formula of the compound is

    A
    `C_2H_4O_2`
    B
    `C_4H_6O`
    C
    `C_3H_8O`
    D
    `CH_2O`

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