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The point diametrically opposite to the ...

The point diametrically opposite to the point P(1, 0) on the circle `x^(2)+y^(2)+2x+4y-3=0` is

A

(3,4)

B

(3,-4)

C

(-3,4)

D

(-3,-4)

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • The point diametrically opposite to the point (6, 0) on the circle x^(2) +y^(2)-4x+6y-12=0 is :

    A
    (2, 6)
    B
    (-2, 6)
    C
    (2, -6)
    D
    (-2, -6)

  • An equation of the normal at the point (2,3)to the circle x ^(2)+ y^(2) - 2x - 2y - 3=0 is

    A
    `2x + y - 7=0`
    B
    `x + 2y - 3=0`
    C
    `2x-y-1 =0`
    D
    `x - 2y + 1=0`

  • Point (1,2) relative to the circle x^(2) + y^(2) + 4x - 2y - 4 = 0 is a/an

    A
    exterior point
    B
    interior point, but not centre
    C
    boundary point
    D
    centre

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