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If f:RrarrR defined by f(x)=x^(2)-2x+3, ...

If `f:RrarrR` defined by `f(x)=x^(2)-2x+3`, then find `f(f(x))`.

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To find \( f(f(x)) \) for the function \( f(x) = x^2 - 2x + 3 \), we will follow these steps: ### Step 1: Write down the function We start with the function: \[ f(x) = x^2 - 2x + 3 \] ### Step 2: Substitute \( f(x) \) into itself To find \( f(f(x)) \), we need to substitute \( f(x) \) into the function \( f \): \[ f(f(x)) = f(x^2 - 2x + 3) \] ### Step 3: Replace \( x \) in \( f(x) \) with \( x^2 - 2x + 3 \) Now we will replace \( x \) in the original function with \( x^2 - 2x + 3 \): \[ f(f(x)) = (x^2 - 2x + 3)^2 - 2(x^2 - 2x + 3) + 3 \] ### Step 4: Expand \( (x^2 - 2x + 3)^2 \) We need to expand \( (x^2 - 2x + 3)^2 \): \[ (x^2 - 2x + 3)^2 = x^4 - 4x^3 + 6x^2 - 4x + 9 \] ### Step 5: Expand \( -2(x^2 - 2x + 3) \) Next, we expand \( -2(x^2 - 2x + 3) \): \[ -2(x^2 - 2x + 3) = -2x^2 + 4x - 6 \] ### Step 6: Combine all parts Now we combine all the parts together: \[ f(f(x)) = (x^4 - 4x^3 + 6x^2 - 4x + 9) + (-2x^2 + 4x - 6) + 3 \] ### Step 7: Simplify the expression Now, we simplify the expression: \[ f(f(x)) = x^4 - 4x^3 + (6x^2 - 2x^2) + (-4x + 4x) + (9 - 6 + 3) \] \[ = x^4 - 4x^3 + 4x^2 + 6 \] ### Final Answer Thus, the final answer is: \[ f(f(x)) = x^4 - 4x^3 + 4x^2 + 6 \] ---
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Knowledge Check

  • If f:RrarrR is defined by f(x)=x^(2)+1 , then value of f^(-1)(17)andf^(-1)(-3) resepctively are

    A
    `phi{4,-4}`
    B
    `{3,-3}phi`
    C
    `phi{3,-3}`
    D
    `{4,-4}phi`
  • Let f:RrarrR be defined as f(x)=x^(4) . Then :

    A
    f is one-one onto
    B
    f is many-one onto
    C
    f is one-one but not onto
    D
    f is neither one-one nor onto
  • Let f:RrarrR be defined as f(x)=2x .

    A
    f is one-one onto
    B
    f is many-one onto
    C
    f is one-one but not onto
    D
    f is neither one-one nor onto
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