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Find all the co-factors of |{:(1,3),(-2,...

Find all the co-factors of `|{:(1,3),(-2,4):}|`

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To find all the co-factors of the determinant given by the matrix: \[ \begin{pmatrix} 1 & 3 \\ -2 & 4 \end{pmatrix} \] we will follow the steps to calculate the co-factors \( C_{ij} \) for each element in the matrix. ### Step 1: Identify the matrix and its elements The matrix is: \[ A = \begin{pmatrix} 1 & 3 \\ -2 & 4 \end{pmatrix} \] The elements of the matrix are: - \( a_{11} = 1 \) - \( a_{12} = 3 \) - \( a_{21} = -2 \) - \( a_{22} = 4 \) ### Step 2: Calculate the co-factor \( C_{11} \) The co-factor \( C_{11} \) is calculated using the formula: \[ C_{ij} = (-1)^{i+j} \cdot M_{ij} \] where \( M_{ij} \) is the minor of the element \( a_{ij} \). For \( C_{11} \): - \( i = 1, j = 1 \) - The minor \( M_{11} \) is the determinant of the matrix obtained by removing the first row and first column: \[ M_{11} = \begin{vmatrix} 4 \end{vmatrix} = 4 \] Thus, \[ C_{11} = (-1)^{1+1} \cdot 4 = 1 \cdot 4 = 4 \] ### Step 3: Calculate the co-factor \( C_{12} \) For \( C_{12} \): - \( i = 1, j = 2 \) - The minor \( M_{12} \) is the determinant of the matrix obtained by removing the first row and second column: \[ M_{12} = \begin{vmatrix} -2 \end{vmatrix} = -2 \] Thus, \[ C_{12} = (-1)^{1+2} \cdot (-2) = -1 \cdot (-2) = 2 \] ### Step 4: Calculate the co-factor \( C_{21} \) For \( C_{21} \): - \( i = 2, j = 1 \) - The minor \( M_{21} \) is the determinant of the matrix obtained by removing the second row and first column: \[ M_{21} = \begin{vmatrix} 3 \end{vmatrix} = 3 \] Thus, \[ C_{21} = (-1)^{2+1} \cdot 3 = -1 \cdot 3 = -3 \] ### Step 5: Calculate the co-factor \( C_{22} \) For \( C_{22} \): - \( i = 2, j = 2 \) - The minor \( M_{22} \) is the determinant of the matrix obtained by removing the second row and second column: \[ M_{22} = \begin{vmatrix} 1 \end{vmatrix} = 1 \] Thus, \[ C_{22} = (-1)^{2+2} \cdot 1 = 1 \cdot 1 = 1 \] ### Summary of the co-factors The co-factors of the matrix are: - \( C_{11} = 4 \) - \( C_{12} = 2 \) - \( C_{21} = -3 \) - \( C_{22} = 1 \) Thus, the co-factors of the matrix are: \[ \begin{pmatrix} 4 & 2 \\ -3 & 1 \end{pmatrix} \]
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Knowledge Check

  • If C_(ij) is the co-factor of a_(ij) and A={:[(1,2,3),(2,3,2),(1,2,2)]:} then

    A
    `C_(12)+C_(22)+C_(32)=0`
    B
    `C_(13)+C_(23)+C_(33)=1`
    C
    `C_(11)+C_(21)=C_(32)`
    D
    `C_(11)+C_(22)+C_(33)`
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