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K(2)SO(4) solution mixed with Cr(2)(SO(4...

`K_(2)SO_(4)` solution mixed with `Cr_(2)(SO_(4))_(3)` solution in 1:1 molar ratio gives the test of `Cr^(3+)` ion but `CuSO_(4)` solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of `Cu^(2+)` ion. Explain why ?

Text Solution

Verified by Experts

`K_(2)SO_(4).Cr_(2)(SO_(4))_(3) overset(aq)iff2K^(+)(aq)+2Cr^(3+)(aq)+4SO_(4)^(2-)`
So chrome alum is double salt. It when dissolved in water gives its constituent ions. Hence it gives the test of `K^(+),Cr^(3+) and SO_(4)^(2-)` ions.
`CuSO_(4).4NH_(3)[Cu(NH_(3))_(4)SO_(4) overset(aq)iff[Cu(NH_(3))_(4)]^(2+)(aq)+SO_(4)^(2-)(aq)`
As copper (II) is present in coordination sphere it will not given the test of `Cu^(2+)` ion.
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FeSO_(4) solution mixed with (NH_(4))_(2)SO_(4) solution in 1 : 1 molar ratio gives the test of Fe^(2+) ion but CuSO_(4) solution mixed with aqueous ammonia in 1 : 4 molar ratio does not give the test of Cu^(2+) ion. Explain, why ?

FeSO_(4) solution mixed with (NH_(4))_(2)SO_(4) solution in 1 : 1 molar ratio gives the test of Fe^(2+) but CuSO_(4) solution mixed with aqueous ammonia in 1 : 4 molar ratio does not give the test of Cu^(2+) ion. Explain why ?

Knowledge Check

  • KI and CuSO_4 solutions when mixed give

    A
    `CuI_2+K_2SO_4`
    B
    `Cu_2I_2+K_2SO_4`
    C
    `K_2SO_4+Cu_2I_2+I_2`
    D
    `K_2SO_4+CuI_2+I_2`
  • KI and CuSO_4 solution when mixed give .

    A
    `Cu l_2 + K_2SO_4`
    B
    `Cu_2I_2 + K_2SO_4`
    C
    `K_2SO_4 + CU_2I_2 +I_2`
    D
    `K_2SO_4 + CuI_2I_2`
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    A
    `K_(2)[Fe(CN)_(4)]`
    B
    `K_(3)[Fe(CN)_(5)]`
    C
    `K_(3)[Fe(CN)_(6)]`
    D
    `K_(4)[Fe(CN)_(6)]`
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