Find the the valency factor for following acids
`(i) CH_(3)CO OH " " (ii) NaH_(2)PO_(4) " " (iii) H_(3)BO_(3)`

Answer

To find the valency factor for the given acids, we need to determine the number of hydrogen ions (H⁺) that each acid can release in aqueous solution. Let's analyze each acid step by step.

### Step 1: Determine the valency factor for CH₃COOH (Acetic Acid)

1. **Identify the structure**: Acetic acid (CH₃COOH) has the following structure:
- CH₃ (methyl group) attached to COOH (carboxylic group).

2. **Identify acidic hydrogen**: In acetic acid, the hydrogen in the -COOH group is the only acidic hydrogen. The three hydrogens in the -CH₃ group are not acidic and cannot be released.

3. **Conclusion**: Since only one H⁺ ion can be released, the valency factor for CH₃COOH is **1**.

### Step 2: Determine the valency factor for NaH₂PO₄ (Sodium Dihydrogen Phosphate)

1. **Identify the structure**: Sodium dihydrogen phosphate (NaH₂PO₄) has the following structure:
- Central phosphorus atom bonded to four oxygen atoms, with two of these oxygen atoms each having a hydrogen atom.

2. **Identify acidic hydrogens**: The two hydrogens attached to the oxygen atoms are acidic and can be released as H⁺ ions.

3. **Conclusion**: Since two H⁺ ions can be released, the valency factor for NaH₂PO₄ is **2**.

### Step 3: Determine the valency factor for H₃BO₃ (Boric Acid)

1. **Identify the structure**: Boric acid (H₃BO₃) has the following structure:
- A boron atom bonded to three hydroxyl groups (-OH).

2. **Identify acidic hydrogen**: The three hydrogens in the hydroxyl groups are generally considered non-acidic. However, when boric acid reacts with water, it can accept a hydroxide ion (OH⁻) and release one H⁺ ion.

3. **Conclusion**: Therefore, the valency factor for H₃BO₃ is **1**.

### Final Answers

- Valency factor for CH₃COOH: **1**
- Valency factor for NaH₂PO₄: **2**
- Valency factor for H₃BO₃: **1**