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How much will the reduction potential of...

How much will the reduction potential of a hydrogen electrode change when its solution initially at `pH=0` is neutralized to `pH=7` ?

A

increase by `0.059V`

B

decrease by `0.059V`

C

increase by 0.41 V

D

decrease by 0.41 V

Text Solution

Verified by Experts

The correct Answer is:
D

`H^(+)+e^(-)to(1)/(2)H_(2),E=0-(0.0591)/(1)log_(10)((1)/([H^(+)]))=+0.591log_(10)[H^(+)]`
`E_(1)=0{pH=0}`
`E_(2)=+0.0591log_(10)[10^(-7)]=-0.0591xx7{atpH=7}=-0.41V`
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Knowledge Check

  • How much will the reduction potential of a hydrogen electrod echange when its solution initially at pH=0 is neutralized to pH=7?

    A
    Increases by 0.059 V
    B
    Decreases by 0.59 V
    C
    Increases by 0.41 V
    D
    Decreases by 0.41 V
  • How much will be reduction potential of a hydrogen electrolyte change when its solution initially at pH =0 is neutralised to pH=7

    A
    Increase by 0.059 V
    B
    Decrease by 0.059 V
    C
    Increase by 0.41 V
    D
    Decrease by 0.41 V
  • How much will be reduction potential of a hydrogen electrolyte change when its solution initially at pH =0 is neutralised to pH=7

    A
    Increase by 0.059 V
    B
    Decrease by 0.059 V
    C
    Increase by 0.41 V
    D
    Decrease by 0.41 V
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