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Oxalic acid, H(2)C(2)O(4), reacts with p...

Oxalic acid, `H_(2)C_(2)O_(4)`, reacts with paramagnet ion according to the balanced equation `5H_(2)C_(2)O_(4)(aq)+2MnO_(4)^(-)hArr2Mn^(2+)(aq)+10CO_(2)(g)+8H_(2)O(l)`. The volume in mL of 0.0162 M `KMnO_(4)` solution required to react with 25.0 mL of 0.022 M `H_(2)C_(2)O_(4)` solution is :

A

13.6

B

18.5

C

33.8

D

84.4

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Calculate the volume of 0.05 M KMnO_(4) solution required to oxidise completely 2.70 of oxalic acid (H_(2)C_(2)O_(4)) in acidic medium

Calculate the volume of 0.05 M KMnO_(4) solution required to oxidise completely 2.70 of oxalic acid (H_(2)C_(2)O_(4)) in acidic medium

Knowledge Check

  • Oxalic acid, H_(2)C_(2)O_(4) , reacts with paramagnet ion according to the balanced equation 5H_(2)C_(2)O_(4)(aq)+2MnO_(4)^(-)(aq)+6H^(+)(aq)hArr2Mn^(2+)(aq)+10CO_(2)(g)+8H_(2)O(l) . The volume in mL of 0.0162 M KMnO_(4) solution required to react with 25.0 mL of 0.022 M H_(2)C_(2)O_(4) solution is

    A
    13.6
    B
    18.5
    C
    33.8
    D
    84.4

  • 5H_(2)C_(2)O_(4)(aq)+2MnO_(4)(aq)+6H^(+)(aq) to 2Mn^(2+)(aq)+10CO_(2)(g)+8H_(2)O(l) Oxalic acid, H_(2)C_(2)O_(2) , reacts with permanganate ion accroding to the balanced equation above. How many mL of 0.0154 M KMnO_(4) solution are required to react with 25.0mL of 0.208 M H_(2)C_(2)O_(4) solution?

    A
    13.5mL
    B
    18.5mL
    C
    33.8mL
    D
    84.4mL

  • KMnO_(4) react with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O , here 20 ml of 0.1 M KMnO_(4) is equivalemt to

    A
    (a)`20 "ml of" 0.5 M H_(2)C_(2)O_(4)`
    B
    (b)`50 "ml of" 0.1 M H_(2)C_(2)O_(4)`
    C
    (c )`50 " ml of" 0.5 M H_(2)C_(2)O_(4)`
    D
    (d)`20 "ml of" 0.1 M H_(2)C_(2)O_(4)`

    • Similar Questions

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    KMnO_(4) reacts with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20 mL of 0.1 M KMnO_(4) is equivalent to :

    KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20 mL of 0.1 M KMnO_(4) is equivalent to:

    KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

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    KMnO_(4) reacts with oxalic acid according to the equation: 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to2Mn^(2+)+10CO_(2)+8H_(2)O 20mL of 0.1M KMnO_(4) will react with:

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