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A series LR circuit is connected to a vo...

A series LR circuit is connected to a voltage source with V(t) = `V_(0)` sin `omega` t. after very large time, current I(t) behaves as `(t_(0) gt gt (L)/(R))`

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
(b) : Current will also be sinusoidal although there is phase difference between voltage and current .
Hence option (B) is correct .
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Knowledge Check

  • A seris LR circuit is connected to a voltage source with V(t) = V_(0)sin omegat . After very large time, current 1(t) behaves as (t_(0) gt gt (L)/(R)) :

    A
    B
    C
    D

  • A capacitor of capacity C is connected in A.C circuit. If the applied emf is V = V_(0) sin omega t , then the current is

    A
    `I = (V_(0))/(L omega) sin omega t`
    B
    `I = (V_(0))/(omega C) sin (omega t + (pi)/(2))`
    C
    `I = V_(0) C omega sin omega t`
    D
    `t = V_(0) C omega sin (omega t + (pi)/(2))`

  • In an AC circuit the voltage applied is E = E_(0) sin omega t . The resulting current in the circuit is I = I_(0) sin (omega t - (pi)/(2)) . The power consumption in the circuit is given by

    A
    `P = (E_(0) I_(0))/(sqrt(2))`
    B
    `P =` zero
    C
    `P = (E_(0)I_(0))/(2)`
    D
    `P = sqrt(2) E_(0) I_(0)`

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