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An alpha-particle with kinetic energy K ...

An `alpha`-particle with kinetic energy `K` is heading towards a stationary nucleus of atomic number `Z`. Find the distance of the closest approach.

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Knowledge Check

  • A beam of beryllium nucleus (z = 4) of kinetic energy 5.3 MeV is headed towards the nucleus of gold atom (Z = 79). What is the distance of closest approach?

    A
    `10.32xx10^(-14)m`
    B
    `8.58xx10^(-14)m`
    C
    `3.56xx10^(-14)m`
    D
    `1.25xx10^(-14)m`

  • The distance of the closest approach of an alpha particle fired at a nucleus with kinetic of an alpha particle fired at a nucleus with kinetic energy K is r_(0) . The distance of the closest approach when the alpha particle is fired at the same nucleus with kinetic energy 2K will be

    A
    `4 r_(0)`
    B
    `r_(0)/2`
    C
    `r_(0)/4`
    D
    `2r_(0)`

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    An alpha - particle moving with initial kinetic energy K towards a nucleus of atomic number z approaches a distance 'd' at which it reverse its direction. Obtain the expression for the distance of closest approach 'd' in terms of the kinetic energy of alpha - particle K.

    An alpha -particle moving with initial kinetic energy 'K' towards a nucleus of atomic number Z approaches a distance ' r_(0) ' at which it reverses its direction. Obtain the expression for the distance of closest approach ' r_(0) ' in terms of kinetic energy of a particle.

    An alpha -particle of kinetic energy 7.68 MeV is projected towards the nucleus of copper (Z=29). Calculate its distance of nearest approach.

    Define distance of the closest approach. An alpha - particle of kinetic energy K is bombarded on a thin gold foil. The distance of the closest approach is r . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ?

    Define the distance of closest approach. An alpha -particle of kinetic enegy 'K' is bombarded on a thin gold foil. The distance of the closest approach is 'r' . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ?

    Define the distance of closest approach. An a-particle of kinetic energy 'K' is bombarded on a thin gold foil. The distance of the closest approach is 'Y. What will be the distance of closest approach for an a-particle of double the kinetic energy?

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