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Two photosensitive X and Y are exposed t...

Two photosensitive X and Y are exposed to radiations of frequency `10^(12)Hz`. Comment on threshold frequency of each surface if photoelectrons emitted from surface X have zero kinetic energy and that from surface Y have some positive kinetic energy .

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To solve the problem, we need to analyze the situation based on the information provided about the two photosensitive surfaces, X and Y, and their interaction with the radiation of frequency \(10^{12} \text{ Hz}\). ### Step-by-Step Solution: 1. **Understand the Concept of Threshold Frequency**: The threshold frequency (\( \nu_0 \)) is the minimum frequency of incident light required to emit photoelectrons from a material. If the frequency of the incident light is less than \( \nu_0 \), no photoelectrons will be emitted. If the frequency is equal to or greater than \( \nu_0 \), photoemission can occur. 2. **Given Information**: ...
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Knowledge Check

  • When light falls on a photosensitive surface, electrons are emitted from the surface. The kinetic energy of these electrons does not depend on the:

    A
    Wavelength of light
    B
    thickness of the surface layer
    C
    type of material used for the layer
    D
    Intensity of light
  • When the photons of energy hv fall on a photosensitive metallic surface of work function hv_(0) , electrons are emitted are from jthe surface. The most energetic electron coming out of the surfece have kinetic energy equal to

    A
    `hv`
    B
    `hv_(0)`
    C
    `hv+hv_(0)`
    D
    `hv-hv_(0)`
  • The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 e V fall on it is 4 eV. The stopping potential in volt is:

    A
    4
    B
    6
    C
    8
    D
    10
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