Find the (a) maximum frequency and (b) minimum wave-length of X-rays produced by 30 kV electrons. Given, `h=6.63xx10^(-34)Js`.

Explanation

Given , accelerating voltage , `V_0=30 kV = 30 xx10^3V`
(a) Maximum kinetic energy is given by
`K_(max)=eV_0`
So `hv_(max)=eV_0`
where `v_(max)` is the maximum frequency
`impliesv_(max)=(eV_0)/h`
`implies v_(max)=(1.6xx10^(-19)xx30xx10^3)/(6.63xx10^(-34))`
`=7.24xx10^(18)Hz`
(b) Minimum wavelength is given by
`lamda_(min)=c/(v_(max))=(3xx10^8)/(7.24xx10^(18))`
`=0.041xx10^(-9)`
`implies lamda_(min)=0.041 nm`