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A particle is droped from a height H. Th...

A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional to

A

H

B

`H^(1//2)`

C

`H^0`

D

`H^(-1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Velocity attained by the particle after falling from a height H is
`v=sqrt(2gH)`
Where g = acceleration due to gravity
The de Brolige wavelength is given by
`lamda=h//p=h/(mv)=h/(msqrt2gH)`
Where m is the mass and p is the momentum of particle
`:.lamdaprop1/sqrtH" or "lamdapropH^(-1//2)`
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Knowledge Check

  • A particle is droped from a height H. The de-broglie wavelength of the particle as a funciton of height is proportional to

    A
    `H`
    B
    `H^(1//2)`
    C
    `H^(0)`
    D
    `H^(-1//2)`

  • A particle is dropped from a height H. the de-Broglie wavelength of the particle depends on height as

    A
    `H^(-1//2)`
    B
    `H^(0)`
    C
    `H^(1//2)`
    D
    `H`

  • The de Broglie wavelength lambda of a particle

    A
    is proportional to mass
    B
    is proportional to impluse
    C
    is inversely proportional to impulse
    D
    does not depend on impulse

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