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Taking the Bohr radius a(0) = 53 pm, the...

Taking the Bohr radius `a_(0) = 53` pm, the radius of `Li^(++)` ion in its gnround state, on the basis of Bohr's model, will be about.

A

53 pm

B

27 pm

C

18 pm

D

13 pm

Text Solution

Verified by Experts

The correct Answer is:
c
According to Bohr.s model, Radius of `n^(th)` orbit of atom with atomic number Z is given by
`r_n=(n^2a_0)/Z`
where `a_0` = Bohr.s radius (radius of first orbit of hydrogen atom )
Given, `a_0`=53 pm
For `Li^(+ +)` ion ,
Z=3 and n=1 (ground state)
`therefore ` Radius is given by
`r_1=(1^2xx"53 pm")/3=17.67 approx` 18 pm
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