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Taking the Bohr radius a(0) = 53 pm, the...

Taking the Bohr radius `a_(0) = 53` pm, the radius of `Li^(++)` ion in its gnround state, on the basis of Bohr's model, will be about.

A

53 pm

B

27 pm

C

18 pm

D

13 pm

Text Solution

Verified by Experts

The correct Answer is:
c
According to Bohr.s model, Radius of `n^(th)` orbit of atom with atomic number Z is given by
`r_n=(n^2a_0)/Z`
where `a_0` = Bohr.s radius (radius of first orbit of hydrogen atom )
Given, `a_0`=53 pm
For `Li^(+ +)` ion ,
Z=3 and n=1 (ground state)
`therefore ` Radius is given by
`r_1=(1^2xx"53 pm")/3=17.67 approx` 18 pm
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Knowledge Check

  • Taking the Bohr radius as r_(0)=53 pm, the radius of Li^( + +) ion in its ground state, on the basis of Bohrs model, will be a about

    A
    53pm
    B
    27pm
    C
    18pm
    D
    13pm

  • Find the radius of Li^(++) ions in its ground state assuming Bohr's model to be valid.

    A
    `12xx10^(-10)m`
    B
    `12xx10^(-12)m`
    C
    `16xx10^(-10)m`
    D
    `18xx10^(-12)m`.

  • What is the radius of the second orbit of helium atom , on the basis of Bohr's atom model ?

    A
    1.06 Å
    B
    2.12 Å
    C
    0.265 Å
    D
    0.53 Å

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