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A stone falls from rest. The total dista...

A stone falls from rest. The total distance covered by it in the last second of its motion is equal to the distance covered by it in the first three seconds of its motion. How long does the stone remain in air?

A

4 s

B

5 s

C

6 s

D

7 s

Text Solution

Verified by Experts

The correct Answer is:
b
Let the stone remain in air for n seconds then the distance covered in nth second `x=0+(10)/(2)(2n-1)` or x=10n-5: Also the distance covered in first three second is
`=0+(1)/(2)xx10xx9=45`
`:.10n -5 5=45` or n=5 seconds
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Knowledge Check

  • A stone falling from the top of a tower covers half of its height in the last second of its motion, the total height is :

    A
    57 m
    B
    27 m
    C
    37 m
    D
    47 m

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  • For the velocity time graph shown in the figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds ?

    A
    `1/2`
    B
    `1/4`
    C
    `1/3`
    D
    `2/3`

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