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The torque of a force vecF=-3hati+hatj+5...

The torque of a force `vecF=-3hati+hatj+5hatk` acting at a point is `vectau`. If the position vector of the point vector of the point is `7hati+3hatj+hatk`, then `vectau` is :

A

`14 hati-hatj+3 hatk`

B

`7 hati-8 hatj+9 hatk`

C

`2 hati - 3 hatj+8 hatk`

D

`14hat i-38 hatj+16 hatk`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Find the torque of a force vec(F)=-3hat(i) + hatj + 5hatk acting at a point vec(r ) = 7hati + 3hatj + hatk

    A
    `14hati - 38hatj + 16hatk`
    B
    `4 hati - hatj + 6hatk`
    C
    `-14hati+ 38hatj - 16hatk`
    D
    `-21hati + 3hatj + 5hatk`

  • A force vecF=5hati+2hatj-5hatk acts on a particle whose position vector is vecr=hati-2hatj+hatk . What is the torque about the origin?

    A
    `8hati+10hatj+12hatk`
    B
    `8hati+10hatj-12hatk`
    C
    `8hati-10hatj-8hatk`
    D
    `10hati-10hatj-hatk`

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