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In a reaction between hydrogen and iodin...

In a reaction between hydrogen and iodine `6.84 mol` of hydrogen and `4.02` mol of iodine are found to be in equilibrium with `42.85` mol of hydrogen iodine at `350^(@)C.` Calculate the equilibrium constant.

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The reaction is
`{:(,H_2+, I_2 hArr , 2HI),("Equi conc.", 0.92,0.78,6.0):}`
`K_c=[HI]^2/([H_2][I_2])`
`=(6.0)^2/((0.92)xx(0.78))`=50.17
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MODERN PUBLICATION-EQUILIBRIUM-Revision Exercise (Numerical Problems )
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  7. The equilibrium constant K(p) of the reaction: 2SO(2)+O(2) hArr 2SO(3)...

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