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1 M solution each of Cu(NO(3))(2) , AgNO...

1 M solution each of `Cu(NO_(3))_(2)` , `AgNO_(3), Hg_(2)(NO_(3))_(2)andMg(NO_(3))_(2)` is electrolysed using Pt- electrodes . The values of standard electrode potentials in volts are : `Ag^(+)//Ag=+0.80V,Cu^(2+)//Cu=+0.34V Hg_(2)^(2+)//Hg=+0.79V,Mg^(2+)//Mg=-2.37V` The sequence of deposition of metals on the cathode will be

A

`Mg,Ag,Cu`

B

`Mg,Cu,Ag`

C

`Ag,Hg,Cu`

D

`Cu, Hg,Ag`

Text Solution

Verified by Experts

The correct Answer is:
C
Metals get deposuted after undergoing reduction on cathode . Higher the value of reduction potential , more is the tendency to get reduced . Order of `E^(@)` values :
`AggtHggtCu`.
Hence , sequence of deposition : Ag : Hg. Cu.
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Knowledge Check

  • A solution containing one mole per litre of each Cu(NO_(3))_(2), AgNO_(3), Hg_(2)(NO_(3))_(2) and Mg(NO_(3))_(2) is being electrolysed by using electrode potential in volts ( reduction potentials) are Ag^(+)"|"Ag = + 0.80, Hg_(2)^(2+)"|" Hg = 0.79 . Cu^(2+) "|" Cu=0.34" and "Mg^(2+)"|"Mg= - 2.37 V. With increasing voltage, the sequence of deposition of metal on the cathode will be

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