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In Kjeldahl's method, ammonia from 5g of...

In Kjeldahl's method, ammonia from `5g` of food neutralizes `30cm^(3)` of `0.1N` acid. The percentage of nitrogen in the food is

A

`0.84`

B

`8.4`

C

`16.8`

D

`1.68`

Text Solution

Verified by Experts

The correct Answer is:
A
`% "of" N=(1.4xxN_(1)xxV)/(w)`
`=(1.4xx0.1xx30)/(5)`
`=0.84%`
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Knowledge Check

  • In Kjeldahl's method, ammonia from 5 g of food neutralizes "30 cm"^(3) of 0.1 N acid. The percentage of nitrogen in the food is

    A
    `0.84`
    B
    `8.4`
    C
    `16.8`
    D
    1.68`

  • In Kjeldahl's method ammonia from 5 g of food neutralizes 30 cm^3 of 0.1 N acid. the percentage of nitrogen in the food is

    A
    0.84
    B
    8.4
    C
    16.8
    D
    1.68

  • 0.25g of an organic compound on Kjeldahl's analysis gave enough ammonia to just neutralise 10cm^(3) of 0.5M H_(2)SO_(4) . The percentage of nitrogen in the compound is

    A
    `28`
    B
    `56`
    C
    `14`
    D
    `112`

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