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When sulphur dioxide is passed in an aci...

When sulphur dioxide is passed in an acidified `K_(2)Cr_(2)O_(7)` solution , the oxidation state of sulphur is changed from

A

`+4 to +6`

B

`+6 to +4`

C

`+4 to 0`

D

`+4 to +2`.

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(2)CrO_(7)+H_(2)SO_(4)+3overset(+4)(SO_(2))toK_(2)overset(+6)(SO_(4))+Cr_(2)(SO_(4))_(3)+H_(2)O` The oxidation state of S changes from +4 to +6.
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Knowledge Check

  • When SO_2 is passed through acidified K_2Cr_2O_7 solution

    A
    the solution is turned blue
    B
    the solution is decolourised
    C
    `SO_2` is reduced
    D
    green `Cr_2(SO_4)_3` is formed

  • Acidified K_2Cr_2O_7 solution turns green by:

    A
    `CO_2` gas
    B
    `SO_2` gas
    C
    HCl gas
    D
    `H_2S` gas

  • Acidifed K_(2)Cr_(2)O_(7) oxidises H_(2)S to :

    A
    `SO_(2)`
    B
    `SO_(3)`
    C
    S
    D
    `H_(2)SO_(4) + S`

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