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If k(1) and k(2) are rate constants at ...

If `k_(1)` and `k_(2)` are rate constants at temperatures `T_(1)` and `T_(2)` respectively then according to Arrhenius equation :

A

`"log "(k_(2))/(k_(1))=(2.303R)/(E_(a))[(1)/(T_(1))-(1)/(T_(2))]`

B

`log "(k_(2))/(k_(1))=(E_(a))/(2.303R)[(1)/T_(2)-(1)/(T_(1))]`

C

`log "(k_(1))/(k_(2))=(E_(a))/(2.303R)[(1)/T_(1)-(1)/(T_(2))]`

D

`log "(k_(2))/(k_(1))=(E_(a))/(2.303R)[(1)/T_(1)-(1)/(T_(2))]`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • If K _(1) and K_(2) are the rate constants at temperatures T _(1) and T_(2) respectively and E _(a) is the activatino energy, then :

    A
    `log "" (k _(1))/( k _(2)) =- (E _(a))/( 2.303R [(1)/(T _(1))- (1)/(T _(2))]`
    B
    `log "" (k _(2))/(k _(1)) = (E_(a))/(2.303R) [ (1)/(T _(2)) - (1)/(T _(2))]`
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    `log "" (k _(1))/(k _(2)) = (E _(a))/( 2.303) [ (1)/( T _(1) - (1)/(T _(2))]`
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    `log "" (k _(1))/( k _(2)) =- (E _(a))/( 2.303) [ (1)/(T _(2)) - (1)/(T _(1))]`
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